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2a(3a+2)=0
We multiply parentheses
6a^2+4a=0
a = 6; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·6·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*6}=\frac{-8}{12} =-2/3 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*6}=\frac{0}{12} =0 $
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