2/3(6x+3)=8x+12

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Solution for 2/3(6x+3)=8x+12 equation: 



2/3(6x+3)=8x+12

We move all terms to the left:

2/3(6x+3)-(8x+12)=0



Domain of the equation: 3(6x+3)!=0

x∈R



We get rid of parentheses

2/3(6x+3)-8x-12=0

We multiply all the terms by the denominator


-8x*3(6x+3)-12*3(6x+3)+2=0

Wy multiply elements

-24x^2(6-36x(6+2=0

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