8(x-3)-8=-6(x-2)

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Solution for 8(x-3)-8=-6(x-2) equation: 



8(x-3)-8=-6(x-2)

We move all terms to the left:

8(x-3)-8-(-6(x-2))=0

We multiply parentheses

8x-(-6(x-2))-24-8=0



We calculate terms in parentheses: -(-6(x-2)), so:

-6(x-2)

We multiply parentheses

-6x+12

Back to the equation:

-(-6x+12)



We add all the numbers together, and all the variables

8x-(-6x+12)-32=0

We get rid of parentheses

8x+6x-12-32=0

We add all the numbers together, and all the variables

14x-44=0

We move all terms containing x to the left, all other terms to the right

14x=44

x=44/14

x=3+1/7

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