2/3(6k-12)=3k-7

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Solution for 2/3(6k-12)=3k-7 equation: 



2/3(6k-12)=3k-7

We move all terms to the left:

2/3(6k-12)-(3k-7)=0



Domain of the equation: 3(6k-12)!=0

k∈R



We get rid of parentheses

2/3(6k-12)-3k+7=0

We multiply all the terms by the denominator


-3k*3(6k-12)+7*3(6k-12)+2=0

Wy multiply elements

-9k^2(6+21k(6+2=0

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