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-1/5(50-20x)=4x-3
We move all terms to the left:
-1/5(50-20x)-(4x-3)=0
Domain of the equation: 5(50-20x)!=0We add all the numbers together, and all the variables
x∈R
-1/5(-20x+50)-(4x-3)=0
We get rid of parentheses
-1/5(-20x+50)-4x+3=0
We multiply all the terms by the denominator
-4x*5(-20x+50)+3*5(-20x+50)-1=0
Wy multiply elements
-20x^2(-+15x(--1=0
We use the square of the difference formula
-20x^2(-15x(+1=0
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