2/3(5-x)-1/6(7x-5)+(x+6)=7

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Solution for 2/3(5-x)-1/6(7x-5)+(x+6)=7 equation: 



2/3(5-x)-1/6(7x-5)+(x+6)=7

We move all terms to the left:

2/3(5-x)-1/6(7x-5)+(x+6)-(7)=0



Domain of the equation: 3(5-x)!=0

x∈R





Domain of the equation: 6(7x-5)!=0

x∈R



We add all the numbers together, and all the variables

2/3(-1x+5)-1/6(7x-5)+(x+6)-7=0

We get rid of parentheses

2/3(-1x+5)-1/6(7x-5)+x+6-7=0

We calculate fractions


x+(12x7/(3(-1x+5)*6(7x-5))+(-3x(-)/(3(-1x+5)*6(7x-5))+6-7=0

We can not solve this equation

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