2/3(4x-5)+8=1/9(x+4)

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Solution for 2/3(4x-5)+8=1/9(x+4) equation: 



2/3(4x-5)+8=1/9(x+4)

We move all terms to the left:

2/3(4x-5)+8-(1/9(x+4))=0



Domain of the equation: 3(4x-5)!=0

x∈R





Domain of the equation: 9(x+4))!=0

x∈R



We calculate fractions


(18xx/(3(4x-5)*9(x+4)))+(-3x4/(3(4x-5)*9(x+4)))+8=0



We calculate terms in parentheses: +(18xx/(3(4x-5)*9(x+4))), so:

18xx/(3(4x-5)*9(x+4))

We multiply all the terms by the denominator


18xx

Back to the equation:

+(18xx)





We calculate terms in parentheses: +(-3x4/(3(4x-5)*9(x+4))), so:

-3x4/(3(4x-5)*9(x+4))

We multiply all the terms by the denominator


-3x4

We add all the numbers together, and all the variables

-3x^4

We do not support expression: x^4

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