2/3(4x-1)-5x=4/3-3(x+2)

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Solution for 2/3(4x-1)-5x=4/3-3(x+2) equation: 



2/3(4x-1)-5x=4/3-3(x+2)

We move all terms to the left:

2/3(4x-1)-5x-(4/3-3(x+2))=0



Domain of the equation: 3(4x-1)!=0

x∈R





Domain of the equation: 3-3(x+2))!=0

We move all terms containing x to the left, all other terms to the right

-3(x+2))!=-3

x∈R



We add all the numbers together, and all the variables

-5x+2/3(4x-1)-(4/3-3(x+2))=0

We calculate fractions


-5x+(-3(x+2))+2*3)/33x+(-12x4/33x=0



We calculate terms in parentheses: +(-3(x+2)), so:

-3(x+2)

We multiply parentheses

-3x-6

Back to the equation:

+(-3x-6)



We get rid of parentheses

-5x-3x+2*3)/33x+(-12x4/33x-6=0

We calculate fractions

We do not support expression: x^5

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