2x+3(2x-4)=8(x-4)

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Solution for 2x+3(2x-4)=8(x-4) equation: 



2x+3(2x-4)=8(x-4)

We move all terms to the left:

2x+3(2x-4)-(8(x-4))=0

We multiply parentheses

2x+6x-(8(x-4))-12=0



We calculate terms in parentheses: -(8(x-4)), so:

8(x-4)

We multiply parentheses

8x-32

Back to the equation:

-(8x-32)



We add all the numbers together, and all the variables

8x-(8x-32)-12=0

We get rid of parentheses

8x-8x+32-12=0

We add all the numbers together, and all the variables

20!=0

There is no solution for this equation

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