2/3(3y-1)-(y+2)=1/3

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Solution for 2/3(3y-1)-(y+2)=1/3 equation: 


y in (-oo:+oo)

(2/3)*(3*y-1)-y-2 = 1/3 // - 1/3

(2/3)*(3*y-1)-y-(1/3)-2 = 0

(2/3)*(3*y-1)-y-1/3-2 = 0

2/3*(3*y-1)-y-1/3-2 = 0

(2/3*3*(3*y-1))/3+(3*(-y))/3-1/3+(-2*3)/3 = 0

2/3*3*(3*y-1)+3*(-y)-2*3-1 = 0

3*y-6-2-1 = 0

3*y-6-3 = 0

3*y-9 = 0

(3*y-9)/3 = 0

(3*y-9)/3 = 0 // * 3

3*y-9 = 0

3*y-9 = 0 // + 9

3*y = 9 // : 3

y = 9/3

y = 3

y = 3

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