7(x-3)(x+3)=0

Solution for 7(x-3)(x+3)=0 equation:

Simplifying
7(x + -3)(x + 3) = 0

Reorder the terms:
7(-3 + x)(x + 3) = 0

Reorder the terms:
7(-3 + x)(3 + x) = 0

Multiply (-3 + x) * (3 + x)
7(-3(3 + x) + x(3 + x)) = 0
7((3 * -3 + x * -3) + x(3 + x)) = 0
7((-9 + -3x) + x(3 + x)) = 0
7(-9 + -3x + (3 * x + x * x)) = 0
7(-9 + -3x + (3x + x2)) = 0

Combine like terms: -3x + 3x = 0
7(-9 + 0 + x2) = 0
7(-9 + x2) = 0
(-9 * 7 + x2 * 7) = 0
(-63 + 7x2) = 0

Solving
-63 + 7x2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '63' to each side of the equation.
-63 + 63 + 7x2 = 0 + 63

Combine like terms: -63 + 63 = 0
0 + 7x2 = 0 + 63
7x2 = 0 + 63

Combine like terms: 0 + 63 = 63
7x2 = 63

Divide each side by '7'.
x2 = 9

Simplifying
x2 = 9

Take the square root of each side:
x = {-3, 3}