2/3(3x-5)=1/3(8x+8)

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Solution for 2/3(3x-5)=1/3(8x+8) equation: 



2/3(3x-5)=1/3(8x+8)

We move all terms to the left:

2/3(3x-5)-(1/3(8x+8))=0



Domain of the equation: 3(3x-5)!=0

x∈R





Domain of the equation: 3(8x+8))!=0

x∈R



We calculate fractions


(6x8/(3(3x-5)*3(8x+8)))+(-3x3/(3(3x-5)*3(8x+8)))=0



We calculate terms in parentheses: +(6x8/(3(3x-5)*3(8x+8))), so:

6x8/(3(3x-5)*3(8x+8))

We multiply all the terms by the denominator


6x8

We add all the numbers together, and all the variables

6x^8

We do not support expression: x^8

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