5/8x+1/5x=99

Solution for 5/8x+1/5x=99 equation:

5/8x+1/5x=99

We move all terms to the left:

5/8x+1/5x-(99)=0


Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R


We calculate fractions


25x/40x^2+8x/40x^2-99=0

We multiply all the terms by the denominator


25x+8x-99*40x^2=0

We add all the numbers together, and all the variables

33x-99*40x^2=0

Wy multiply elements

-3960x^2+33x=0

a = -3960; b = 33; c = 0;
Δ = b2-4ac
Δ = 332-4·(-3960)·0
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(33)-33}{2*-3960}=\frac{-66}{-7920}
=1/120
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(33)+33}{2*-3960}=\frac{0}{-7920}
=0
$