2/3(3n-27)=3/4(4n-7)

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Solution for 2/3(3n-27)=3/4(4n-7) equation:



2/3(3n-27)=3/4(4n-7)
We move all terms to the left:
2/3(3n-27)-(3/4(4n-7))=0
Domain of the equation: 3(3n-27)!=0
n∈R
Domain of the equation: 4(4n-7))!=0
n∈R
We calculate fractions
(8n4/(3(3n-27)*4(4n-7)))+(-9n3/(3(3n-27)*4(4n-7)))=0
We calculate terms in parentheses: +(8n4/(3(3n-27)*4(4n-7))), so:
8n4/(3(3n-27)*4(4n-7))
We multiply all the terms by the denominator
8n4
We add all the numbers together, and all the variables
8n^4
We do not support enpression: n^4

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