2(t-(2t+6)+3)=2(t+3)

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Solution for 2(t-(2t+6)+3)=2(t+3) equation: 



2(t-(2t+6)+3)=2(t+3)

We move all terms to the left:

2(t-(2t+6)+3)-(2(t+3))=0



We calculate terms in parentheses: -(2(t+3)), so:

2(t+3)

We multiply parentheses

2t+6

Back to the equation:

-(2t+6)



We get rid of parentheses

2(t-(2t+6)+3)-2t-6=0

We add all the numbers together, and all the variables

-2t+2(t-(2t+6)+3)-6=0

We move all terms containing t to the left, all other terms to the right

-2t+2(t-(2t+6)+3)=6

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