2/3(2x-5)=3/4(x+2)

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Solution for 2/3(2x-5)=3/4(x+2) equation: 



2/3(2x-5)=3/4(x+2)

We move all terms to the left:

2/3(2x-5)-(3/4(x+2))=0



Domain of the equation: 3(2x-5)!=0

x∈R





Domain of the equation: 4(x+2))!=0

x∈R



We calculate fractions


(8xx/(3(2x-5)*4(x+2)))+(-9x2/(3(2x-5)*4(x+2)))=0



We calculate terms in parentheses: +(8xx/(3(2x-5)*4(x+2))), so:

8xx/(3(2x-5)*4(x+2))

We multiply all the terms by the denominator


8xx

Back to the equation:

+(8xx)





We calculate terms in parentheses: +(-9x2/(3(2x-5)*4(x+2))), so:

-9x2/(3(2x-5)*4(x+2))

We multiply all the terms by the denominator


-9x2

We add all the numbers together, and all the variables

-9x^2

Back to the equation:

+(-9x^2)



We get rid of parentheses

-9x^2+8xx=0

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