1/3(2x-5)=3/4(x+2)

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Solution for 1/3(2x-5)=3/4(x+2) equation:



1/3(2x-5)=3/4(x+2)
We move all terms to the left:
1/3(2x-5)-(3/4(x+2))=0
Domain of the equation: 3(2x-5)!=0
x∈R
Domain of the equation: 4(x+2))!=0
x∈R
We calculate fractions
(4xx/(3(2x-5)*4(x+2)))+(-9x2/(3(2x-5)*4(x+2)))=0
We calculate terms in parentheses: +(4xx/(3(2x-5)*4(x+2))), so:
4xx/(3(2x-5)*4(x+2))
We multiply all the terms by the denominator
4xx
Back to the equation:
+(4xx)
We calculate terms in parentheses: +(-9x2/(3(2x-5)*4(x+2))), so:
-9x2/(3(2x-5)*4(x+2))
We multiply all the terms by the denominator
-9x2
We add all the numbers together, and all the variables
-9x^2
Back to the equation:
+(-9x^2)
We get rid of parentheses
-9x^2+4xx=0

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