2/3(2x-1)-3/4(3-2x)=2x-20/9

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Solution for 2/3(2x-1)-3/4(3-2x)=2x-20/9 equation: 



2/3(2x-1)-3/4(3-2x)=2x-20/9

We move all terms to the left:

2/3(2x-1)-3/4(3-2x)-(2x-20/9)=0



Domain of the equation: 3(2x-1)!=0

x∈R





Domain of the equation: 4(3-2x)!=0

x∈R



We add all the numbers together, and all the variables

2/3(2x-1)-3/4(-2x+3)-(+2x-20/9)=0

We get rid of parentheses

2/3(2x-1)-3/4(-2x+3)-2x+20/9=0

We calculate fractions


-2x+(72x(-)/(3(2x-1)*4(-2x+3)*9)+(-81x2/(3(2x-1)*4(-2x+3)*9)+(240x^22/(3(2x-1)*4(-2x+3)*9)=0



We calculate terms in parentheses: +(72x(-)/(3(2x-1)*4(-2x+3)*9)+(-81x2/(3(2x-1)*4(-2x+3)*9)+(240x^22/(3(2x-1)*4(-2x+3)*9), so:

72x(-)/(3(2x-1)*4(-2x+3)*9)+(-81x2/(3(2x-1)*4(-2x+3)*9)+(240x^22/(3(2x-1)*4(-2x+3)*9

We do not support expression: x^22

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