3(8n-4)+2n=7-2(-6n+12)

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Solution for 3(8n-4)+2n=7-2(-6n+12) equation: 



3(8n-4)+2n=7-2(-6n+12)

We move all terms to the left:

3(8n-4)+2n-(7-2(-6n+12))=0

We add all the numbers together, and all the variables

2n+3(8n-4)-(7-2(-6n+12))=0

We multiply parentheses

2n+24n-(7-2(-6n+12))-12=0



We calculate terms in parentheses: -(7-2(-6n+12)), so:

7-2(-6n+12)

determiningTheFunctionDomain
-2(-6n+12)+7

We multiply parentheses

12n-24+7

We add all the numbers together, and all the variables

12n-17

Back to the equation:

-(12n-17)



We add all the numbers together, and all the variables

26n-(12n-17)-12=0

We get rid of parentheses

26n-12n+17-12=0

We add all the numbers together, and all the variables

14n+5=0

We move all terms containing n to the left, all other terms to the right

14n=-5

n=-5/14

n=-5/14

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