2/3(2t-7)+2/3t=-95/3-t=

Solution for 2/3(2t-7)+2/3t=-95/3-t= equation:

2/3(2t-7)+2/3t=-95/3-t=

We move all terms to the left:

2/3(2t-7)+2/3t-(-95/3-t)=0


Domain of the equation: 3(2t-7)!=0

t∈R



Domain of the equation: 3t!=0

t!=0/3

t!=0

t∈R



Domain of the equation: 3-t)!=0

We move all terms containing t to the left, all other terms to the right

-t)!=-3

t!=-3/1

t!=-3

t∈R


We add all the numbers together, and all the variables

2/3(2t-7)+2/3t-(-1t-95/3)=0

We get rid of parentheses

2/3(2t-7)+2/3t+1t+95/3=0

We calculate fractions


1t+6t/(3(2t-7)*3t*3)+(6t2/(3(2t-7)*3t*3)=0


We calculate terms in parentheses: +(6t2/(3(2t-7)*3t*3), so:

6t2/(3(2t-7)*3t*3

We multiply all the terms by the denominator


6t2

We add all the numbers together, and all the variables

6t^2

Back to the equation:

+(6t^2)


determiningTheFunctionDomain
6t^2+1t+6t/(3(2t-7)*3t*3)=0

We add all the numbers together, and all the variables

6t^2+t+6t/(3(2t-7)*3t*3)=0

We multiply all the terms by the denominator


6t^2*(3(2t-7)*3t*3)+t*(3(2t-7)*3t*3)+6t=0

We add all the numbers together, and all the variables

6t^2*(3(2t-7)*3t*3)+6t+t*(3(2t-7)*3t*3)=0