9(j-5)=27

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Solution for 9(j-5)=27 equation: 



9(j-5)=27

We move all terms to the left:

9(j-5)-(27)=0

We multiply parentheses

9j-45-27=0

We add all the numbers together, and all the variables

9j-72=0

We move all terms containing j to the left, all other terms to the right

9j=72

j=72/9

j=8

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