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2/3(15x+9)-3(4x+2)=4(2x+5)-x-12
We move all terms to the left:
2/3(15x+9)-3(4x+2)-(4(2x+5)-x-12)=0
Domain of the equation: 3(15x+9)!=0We multiply parentheses
x∈R
2/3(15x+9)-12x-(4(2x+5)-x-12)-6=0
We multiply all the terms by the denominator
-12x*3(15x+9)-((4(2x+5)-x-12))*3(15x+9)-6*3(15x+9)+2=0
We calculate terms in parentheses: -((4(2x+5)-x-12))*3(15x+9), so:Wy multiply elements
(4(2x+5)-x-12))*3(15x+9
-36x^2(1-((4(2x+5)-x-12))*3(15x+9)-18x(1+2=0
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