4z-3(z-6)=4+2z

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Solution for 4z-3(z-6)=4+2z equation:



4z-3(z-6)=4+2z
We move all terms to the left:
4z-3(z-6)-(4+2z)=0
We add all the numbers together, and all the variables
4z-3(z-6)-(2z+4)=0
We multiply parentheses
4z-3z-(2z+4)+18=0
We get rid of parentheses
4z-3z-2z-4+18=0
We add all the numbers together, and all the variables
-1z+14=0
We move all terms containing z to the left, all other terms to the right
-z=-14
z=-14/-1
z=+14

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