2/3(-3x+3)=1/6(12x-12)

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Solution for 2/3(-3x+3)=1/6(12x-12) equation: 



2/3(-3x+3)=1/6(12x-12)

We move all terms to the left:

2/3(-3x+3)-(1/6(12x-12))=0



Domain of the equation: 3(-3x+3)!=0

x∈R





Domain of the equation: 6(12x-12))!=0

x∈R



We calculate fractions


(12x1/(3(-3x+3)*6(12x-12)))+(-3x0/(3(-3x+3)*6(12x-12)))=0



We calculate terms in parentheses: +(12x1/(3(-3x+3)*6(12x-12))), so:

12x1/(3(-3x+3)*6(12x-12))

We multiply all the terms by the denominator


12x1

We add all the numbers together, and all the variables

12x

Back to the equation:

+(12x)





We calculate terms in parentheses: +(-3x0/(3(-3x+3)*6(12x-12))), so:

-3x0/(3(-3x+3)*6(12x-12))

We multiply all the terms by the denominator


-3x0

We add all the numbers together, and all the variables

-3x

Back to the equation:

+(-3x)



We get rid of parentheses

12x-3x=0

We add all the numbers together, and all the variables

9x=0

x=0/9

x=0

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