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12-1/10x-3/5x=26
We move all terms to the left:
12-1/10x-3/5x-(26)=0
Domain of the equation: 10x!=0
x!=0/10
x!=0
x∈R
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
-1/10x-3/5x-14=0
We calculate fractions
(-5x)/50x^2+(-30x)/50x^2-14=0
We multiply all the terms by the denominator
(-5x)+(-30x)-14*50x^2=0
Wy multiply elements
-700x^2+(-5x)+(-30x)=0
We get rid of parentheses
-700x^2-5x-30x=0
We add all the numbers together, and all the variables
-700x^2-35x=0
a = -700; b = -35; c = 0;
Δ = b2-4ac
Δ = -352-4·(-700)·0
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-35}{2*-700}=\frac{0}{-1400} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+35}{2*-700}=\frac{70}{-1400} =-1/20 $
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