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2/2-5=3-8+h-(1-3)
We move all terms to the left:
2/2-5-(3-8+h-(1-3))=0
We add all the numbers together, and all the variables
-(3-8+h-(-2))-5+2/2=0
We add all the numbers together, and all the variables
-(3-8+h-(-2))-4=0
We calculate terms in parentheses: -(3-8+h-(-2)), so:We get rid of parentheses
3-8+h-(-2)
determiningTheFunctionDomain h+3-8-(-2)
We add all the numbers together, and all the variables
h-3
Back to the equation:
-(h-3)
-h+3-4=0
We add all the numbers together, and all the variables
-1h-1=0
We move all terms containing h to the left, all other terms to the right
-h=1
h=1/-1
h=-1
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