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2/13x+9=3/17x
We move all terms to the left:
2/13x+9-(3/17x)=0
Domain of the equation: 13x!=0
x!=0/13
x!=0
x∈R
Domain of the equation: 17x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
2/13x-(+3/17x)+9=0
We get rid of parentheses
2/13x-3/17x+9=0
We calculate fractions
34x/221x^2+(-39x)/221x^2+9=0
We multiply all the terms by the denominator
34x+(-39x)+9*221x^2=0
Wy multiply elements
1989x^2+34x+(-39x)=0
We get rid of parentheses
1989x^2+34x-39x=0
We add all the numbers together, and all the variables
1989x^2-5x=0
a = 1989; b = -5; c = 0;
Δ = b2-4ac
Δ = -52-4·1989·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5}{2*1989}=\frac{0}{3978} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5}{2*1989}=\frac{10}{3978} =5/1989 $
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