2(2n+2)=7(4n+3)3+8

Solution for 2(2n+2)=7(4n+3)3+8 equation:

2(2n+2)=7(4n+3)3+8

We move all terms to the left:

2(2n+2)-(7(4n+3)3+8)=0

We multiply parentheses

4n-(7(4n+3)3+8)+4=0


We calculate terms in parentheses: -(7(4n+3)3+8), so:

7(4n+3)3+8

We multiply parentheses

84n+63+8

We add all the numbers together, and all the variables

84n+71

Back to the equation:

-(84n+71)


We get rid of parentheses

4n-84n-71+4=0

We add all the numbers together, and all the variables

-80n-67=0

We move all terms containing n to the left, all other terms to the right

-80n=67

n=67/-80

n=-67/80