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2/(x-1)=5/(3x-4)
We move all terms to the left:
2/(x-1)-(5/(3x-4))=0
Domain of the equation: (x-1)!=0
We move all terms containing x to the left, all other terms to the right
x!=1
x∈R
Domain of the equation: (3x-4))!=0We calculate fractions
x∈R
6x/((x-1)*(3x-4)))+(-(5*(x-1))/((x-1)*(3x-4)))=0
We calculate terms in parentheses: -(5*(x-1))/((x-1)*(3x-4))), so:We add all the numbers together, and all the variables
5*(x-1))/((x-1)*(3x-4))
We multiply all the terms by the denominator
5*(x-1))
We multiply parentheses
5x+
We add all the numbers together, and all the variables
5x
Back to the equation:
-(5x)
-5x+6x/((x-1)*(3x-4)))+(=0
We multiply all the terms by the denominator
-5x*((x-1)*(3x-4)))+(+6x=0
We add all the numbers together, and all the variables
6x-5x*((x-1)*(3x-4)))+(=0
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