2.C(n,n)+3C(n,1)-C(n,0)=16

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Solution for 2.C(n,n)+3C(n,1)-C(n,0)=16 equation: 



2.(C.C)+3(C.1)-(C.0)=16

We move all terms to the left:

2.(C.C)+3(C.1)-(C.0)-(16)=0

We add all the numbers together, and all the variables

2.(+C.C)+3(+C.1)-(+C.0)-16=0

We multiply parentheses

2C+3C-(+C.0)-16=0

We get rid of parentheses

2C+3C-C.0-16=0

We add all the numbers together, and all the variables

5C-C.0-16=0

We move all terms containing C to the left, all other terms to the right

5C-C.0=16

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