-3(x-2)+6=5(3x+4)+1

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Solution for -3(x-2)+6=5(3x+4)+1 equation:



-3(x-2)+6=5(3x+4)+1
We move all terms to the left:
-3(x-2)+6-(5(3x+4)+1)=0
We multiply parentheses
-3x-(5(3x+4)+1)+6+6=0
We calculate terms in parentheses: -(5(3x+4)+1), so:
5(3x+4)+1
We multiply parentheses
15x+20+1
We add all the numbers together, and all the variables
15x+21
Back to the equation:
-(15x+21)
We add all the numbers together, and all the variables
-3x-(15x+21)+12=0
We get rid of parentheses
-3x-15x-21+12=0
We add all the numbers together, and all the variables
-18x-9=0
We move all terms containing x to the left, all other terms to the right
-18x=9
x=9/-18
x=-1/2

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