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2.5x+1/2x=-33
We move all terms to the left:
2.5x+1/2x-(-33)=0
Domain of the equation: 2x!=0We add all the numbers together, and all the variables
x!=0/2
x!=0
x∈R
2.5x+1/2x+33=0
We multiply all the terms by the denominator
(2.5x)*2x+33*2x+1=0
We add all the numbers together, and all the variables
(+2.5x)*2x+33*2x+1=0
We multiply parentheses
4x^2+33*2x+1=0
Wy multiply elements
4x^2+66x+1=0
a = 4; b = 66; c = +1;
Δ = b2-4ac
Δ = 662-4·4·1
Δ = 4340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4340}=\sqrt{4*1085}=\sqrt{4}*\sqrt{1085}=2\sqrt{1085}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(66)-2\sqrt{1085}}{2*4}=\frac{-66-2\sqrt{1085}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(66)+2\sqrt{1085}}{2*4}=\frac{-66+2\sqrt{1085}}{8} $
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