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100x^2=100=0
We move all terms to the left:
100x^2-(100)=0
a = 100; b = 0; c = -100;
Δ = b2-4ac
Δ = 02-4·100·(-100)
Δ = 40000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{40000}=200$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-200}{2*100}=\frac{-200}{200} =-1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+200}{2*100}=\frac{200}{200} =1 $
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