2-6t+2(3-t)=(t-5)5-3

Solution for 2-6t+2(3-t)=(t-5)5-3 equation:

2-6t+2(3-t)=(t-5)5-3

We move all terms to the left:

2-6t+2(3-t)-((t-5)5-3)=0

We add all the numbers together, and all the variables

-6t+2(-1t+3)-((t-5)5-3)+2=0

We multiply parentheses

-6t-2t-((t-5)5-3)+6+2=0


We calculate terms in parentheses: -((t-5)5-3), so:

(t-5)5-3

We multiply parentheses

5t-25-3

We add all the numbers together, and all the variables

5t-28

Back to the equation:

-(5t-28)


We add all the numbers together, and all the variables

-8t-(5t-28)+8=0

We get rid of parentheses

-8t-5t+28+8=0

We add all the numbers together, and all the variables

-13t+36=0

We move all terms containing t to the left, all other terms to the right

-13t=-36

t=-36/-13

t=2+10/13