2-5(x+5)=(x-2)-1

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Solution for 2-5(x+5)=(x-2)-1 equation: 



2-5(x+5)=(x-2)-1

We move all terms to the left:

2-5(x+5)-((x-2)-1)=0

We multiply parentheses

-5x-((x-2)-1)-25+2=0



We calculate terms in parentheses: -((x-2)-1), so:

(x-2)-1

We get rid of parentheses

x-2-1

We add all the numbers together, and all the variables

x-3

Back to the equation:

-(x-3)



We add all the numbers together, and all the variables

-5x-(x-3)-23=0

We get rid of parentheses

-5x-x+3-23=0

We add all the numbers together, and all the variables

-6x-20=0

We move all terms containing x to the left, all other terms to the right

-6x=20

x=20/-6

x=-3+1/3

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