2-5(25z-30)=3/4(12z+16)

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Solution for 2-5(25z-30)=3/4(12z+16) equation: 



2-5(25z-30)=3/4(12z+16)

We move all terms to the left:

2-5(25z-30)-(3/4(12z+16))=0



Domain of the equation: 4(12z+16))!=0

z∈R



We multiply parentheses

-125z-(3/4(12z+16))+150+2=0

We multiply all the terms by the denominator


-125z*4(12z+16))-(3+150*4(12z+16))+2*4(12z+16))=0

We add all the numbers together, and all the variables

-125z*4(12z+16))-(3+150*4(12z+16))+2*4(12z=0

Wy multiply elements

-500z^2(1+2400z^2(1=0

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