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(m+2)(m-1)=5m-6
We move all terms to the left:
(m+2)(m-1)-(5m-6)=0
We get rid of parentheses
(m+2)(m-1)-5m+6=0
We multiply parentheses ..
(+m^2-1m+2m-2)-5m+6=0
We get rid of parentheses
m^2-1m+2m-5m-2+6=0
We add all the numbers together, and all the variables
m^2-4m+4=0
a = 1; b = -4; c = +4;
Δ = b2-4ac
Δ = -42-4·1·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$m=\frac{-b}{2a}=\frac{4}{2}=2$
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