2-3z=6z+12

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Solution for 2-3z=6z+12 equation: 



2-3z=6z+12

We move all terms to the left:

2-3z-(6z+12)=0

We get rid of parentheses

-3z-6z-12+2=0

We add all the numbers together, and all the variables

-9z-10=0

We move all terms containing z to the left, all other terms to the right

-9z=10

z=10/-9

z=-1+1/9

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