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4(y-3)=5(2y-6)
We move all terms to the left:
4(y-3)-(5(2y-6))=0
We multiply parentheses
4y-(5(2y-6))-12=0
We calculate terms in parentheses: -(5(2y-6)), so:We get rid of parentheses
5(2y-6)
We multiply parentheses
10y-30
Back to the equation:
-(10y-30)
4y-10y+30-12=0
We add all the numbers together, and all the variables
-6y+18=0
We move all terms containing y to the left, all other terms to the right
-6y=-18
y=-18/-6
y=+3
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