2-3(z+2)=-6-2z

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Solution for 2-3(z+2)=-6-2z equation: 



2-3(z+2)=-6-2z

We move all terms to the left:

2-3(z+2)-(-6-2z)=0

We add all the numbers together, and all the variables

-3(z+2)-(-2z-6)+2=0

We multiply parentheses

-3z-(-2z-6)-6+2=0

We get rid of parentheses

-3z+2z+6-6+2=0

We add all the numbers together, and all the variables

-1z+2=0

We move all terms containing z to the left, all other terms to the right

-z=-2

z=-2/-1

z=+2

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