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3(2x-5)+2=(x+4)
We move all terms to the left:
3(2x-5)+2-((x+4))=0
We multiply parentheses
6x-((x+4))-15+2=0
We calculate terms in parentheses: -((x+4)), so:We add all the numbers together, and all the variables
(x+4)
We get rid of parentheses
x+4
Back to the equation:
-(x+4)
6x-(x+4)-13=0
We get rid of parentheses
6x-x-4-13=0
We add all the numbers together, and all the variables
5x-17=0
We move all terms containing x to the left, all other terms to the right
5x=17
x=17/5
x=3+2/5
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