2-3(n-4)=(n-7)-7n

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Solution for 2-3(n-4)=(n-7)-7n equation: 



2-3(n-4)=(n-7)-7n

We move all terms to the left:

2-3(n-4)-((n-7)-7n)=0

We multiply parentheses

-3n-((n-7)-7n)+12+2=0



We calculate terms in parentheses: -((n-7)-7n), so:

(n-7)-7n

We add all the numbers together, and all the variables

-7n+(n-7)

We get rid of parentheses

-7n+n-7

We add all the numbers together, and all the variables

-6n-7

Back to the equation:

-(-6n-7)



We add all the numbers together, and all the variables

-3n-(-6n-7)+14=0

We get rid of parentheses

-3n+6n+7+14=0

We add all the numbers together, and all the variables

3n+21=0

We move all terms containing n to the left, all other terms to the right

3n=-21

n=-21/3

n=-7

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