1=d-8+(2)

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Solution for 1=d-8+(2) equation: 



1=d-8+(2)

We move all terms to the left:

1-(d-8+(2))=0

We add all the numbers together, and all the variables

-(d-6)+1=0

We get rid of parentheses

-d+6+1=0

We add all the numbers together, and all the variables

-1d+7=0

We move all terms containing d to the left, all other terms to the right

-d=-7

d=-7/-1

d=+7

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