2-1/2x=2x+16

Solution for 2-1/2x=2x+16 equation:

2-1/2x=2x+16

We move all terms to the left:

2-1/2x-(2x+16)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We get rid of parentheses

-1/2x-2x-16+2=0

We multiply all the terms by the denominator


-2x*2x-16*2x+2*2x-1=0

Wy multiply elements

-4x^2-32x+4x-1=0

We add all the numbers together, and all the variables

-4x^2-28x-1=0

a = -4; b = -28; c = -1;
Δ = b2-4ac
Δ = -282-4·(-4)·(-1)
Δ = 768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{768}=\sqrt{256*3}=\sqrt{256}*\sqrt{3}=16\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-16\sqrt{3}}{2*-4}=\frac{28-16\sqrt{3}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+16\sqrt{3}}{2*-4}=\frac{28+16\sqrt{3}}{-8}
$