2+8(x-5)=7-8(x-4)

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Solution for 2+8(x-5)=7-8(x-4) equation: 



2+8(x-5)=7-8(x-4)

We move all terms to the left:

2+8(x-5)-(7-8(x-4))=0

We multiply parentheses

8x-(7-8(x-4))-40+2=0



We calculate terms in parentheses: -(7-8(x-4)), so:

7-8(x-4)

determiningTheFunctionDomain
-8(x-4)+7

We multiply parentheses

-8x+32+7

We add all the numbers together, and all the variables

-8x+39

Back to the equation:

-(-8x+39)



We add all the numbers together, and all the variables

8x-(-8x+39)-38=0

We get rid of parentheses

8x+8x-39-38=0

We add all the numbers together, and all the variables

16x-77=0

We move all terms containing x to the left, all other terms to the right

16x=77

x=77/16

x=4+13/16

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