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(35-w)*w=300
We move all terms to the left:
(35-w)*w-(300)=0
We add all the numbers together, and all the variables
(-1w+35)*w-300=0
We multiply parentheses
-1w^2+35w-300=0
a = -1; b = 35; c = -300;
Δ = b2-4ac
Δ = 352-4·(-1)·(-300)
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{25}=5$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-5}{2*-1}=\frac{-40}{-2} =+20 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+5}{2*-1}=\frac{-30}{-2} =+15 $
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