3(c+7)=3(c-2)

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Solution for 3(c+7)=3(c-2) equation: 



3(c+7)=3(c-2)

We move all terms to the left:

3(c+7)-(3(c-2))=0

We multiply parentheses

3c-(3(c-2))+21=0



We calculate terms in parentheses: -(3(c-2)), so:

3(c-2)

We multiply parentheses

3c-6

Back to the equation:

-(3c-6)



We get rid of parentheses

3c-3c+6+21=0

We add all the numbers together, and all the variables

27!=0

There is no solution for this equation

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