2+5(5z+3)=96+4(3z+3)

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Solution for 2+5(5z+3)=96+4(3z+3) equation: 



2+5(5z+3)=96+4(3z+3)

We move all terms to the left:

2+5(5z+3)-(96+4(3z+3))=0

We multiply parentheses

25z-(96+4(3z+3))+15+2=0



We calculate terms in parentheses: -(96+4(3z+3)), so:

96+4(3z+3)

determiningTheFunctionDomain
4(3z+3)+96

We multiply parentheses

12z+12+96

We add all the numbers together, and all the variables

12z+108

Back to the equation:

-(12z+108)



We add all the numbers together, and all the variables

25z-(12z+108)+17=0

We get rid of parentheses

25z-12z-108+17=0

We add all the numbers together, and all the variables

13z-91=0

We move all terms containing z to the left, all other terms to the right

13z=91

z=91/13

z=7

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