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2+5(2a-5)=-29+4(2a+4)
We move all terms to the left:
2+5(2a-5)-(-29+4(2a+4))=0
We multiply parentheses
10a-(-29+4(2a+4))-25+2=0
We calculate terms in parentheses: -(-29+4(2a+4)), so:We add all the numbers together, and all the variables
-29+4(2a+4)
determiningTheFunctionDomain 4(2a+4)-29
We multiply parentheses
8a+16-29
We add all the numbers together, and all the variables
8a-13
Back to the equation:
-(8a-13)
10a-(8a-13)-23=0
We get rid of parentheses
10a-8a+13-23=0
We add all the numbers together, and all the variables
2a-10=0
We move all terms containing a to the left, all other terms to the right
2a=10
a=10/2
a=5
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