2+4x-10+6x=2x(5x-4)

Solution for 2+4x-10+6x=2x(5x-4) equation:

2+4x-10+6x=2x(5x-4)

We move all terms to the left:

2+4x-10+6x-(2x(5x-4))=0

We add all the numbers together, and all the variables

10x-(2x(5x-4))-8=0


We calculate terms in parentheses: -(2x(5x-4)), so:

2x(5x-4)

We multiply parentheses

10x^2-8x

Back to the equation:

-(10x^2-8x)


We get rid of parentheses

-10x^2+10x+8x-8=0

We add all the numbers together, and all the variables

-10x^2+18x-8=0

a = -10; b = 18; c = -8;
Δ = b2-4ac
Δ = 182-4·(-10)·(-8)
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2}{2*-10}=\frac{-20}{-20}
=1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2}{2*-10}=\frac{-16}{-20}
=4/5
$